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Resource type The number 'e' - Trevor Hawkes
Trevor Hawkes discusses the number 'e', its relationship to other numbers - 0, pi and i - and its relevance to everyday life. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type The number 'e' - Trevor Hawkes
Trevor Hawkes discusses the number 'e', its relationship to other numbers - 0, pi and i - and its relevance to everyday life. The video is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type The form Rcos(x-a)
In this unit we explore how the sum of two trigonometric functions e.g.3 cos x plus 4 sin x, can be expressed as a single trigonometric function. Having the ability to do this enables us to solve trigonometric equations and find maximum and minimum values. (Mathtutor Video Tutorial) The video is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Rules of arithmetic
Evaluating expressions involving numbers is one of the basic tasks in arithmetic. But if an expression is complicated then it may not be clear which part of it should be evaluated first, and so some rules must be established. There are also rules for calculating with negative numbers. (Mathtutor Video Tutorial) The video is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type The modulus and argument of a complex number
This video explains how to calculate the modulus and argument of a complex number. Sigma resource Unit 9. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by mathcentre.
Resource type Implicit Differentiation
Sometimes functions are given not in the form y=f(x) but in a more complicated form in which it is difficult or impossible to express y explicitly in terms of x.. Such functions are called implicit functions. In this unit we explain how these can be differentiated using implicit differentiation. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Implicit Differentiation
Sometimes functions are given not in the form y=f(x) but in a more complicated form in which it is difficult or impossible to express y explicitly in terms of x.. Such functions are called implicit functions. In this unit we explain how these can be differentiated using implicit differentiation. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type The modulus and argument of a complex number
This mobile phone video explains how to calculate the modulus and argument of a complex number. Sigma resource Unit 9. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by mathcentre.
Resource type Simultaneous Linear Equations Part 1
IPOD VIDEO: The purpose of this section is to look at the solution of simultaneous linear equations. We will see that solving a pair of simultaneous equations is equivalent to finding the location of the point of intersection of two straight lines. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Simultaneous Linear Equations Part 2
IPOD VIDEO: The purpose of this section is to look at the solution of simultaneous linear equations. We will see that solving a pair of simultaneous equations is equivalent to finding the location of the point of intersection of two straight lines. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Simultaneous Linear Equations Part 3
IPOD VIDEO: The purpose of this section is to look at the solution of simultaneous linear equations. We will see that solving a pair of simultaneous equations is equivalent to finding the location of the point of intersection of two straight lines. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Simultaneous Linear Equations Part 4
IPOD VIDEO: The purpose of this section is to look at the solution of simultaneous linear equations. We will see that solving a pair of simultaneous equations is equivalent to finding the location of the point of intersection of two straight lines. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Simultaneous Linear Equations Part 5
IPOD VIDEO: The purpose of this section is to look at the solution of simultaneous linear equations. We will see that solving a pair of simultaneous equations is equivalent to finding the location of the point of intersection of two straight lines. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Simultaneous Linear Equations Part 6
IPOD VIDEO: The purpose of this section is to look at the solution of simultaneous linear equations. We will see that solving a pair of simultaneous equations is equivalent to finding the location of the point of intersection of two straight lines. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Simultaneous Linear Equations Part 7
IPOD VIDEO: The purpose of this section is to look at the solution of simultaneous linear equations. We will see that solving a pair of simultaneous equations is equivalent to finding the location of the point of intersection of two straight lines. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Solving Cubic Equations
All cubic equations have either one real root, or three real roots. In this video we explore why this is so. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type minus x minus = plus - Mike Savage
This mathtutor extention video explains how multiplying a negative number by another negative number gives a positive number. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Triangular numbers - Alyson Stibbard
In this mathtutor extention video, Alyson Stibbard explores triangular numbers, dicusses their properties and explains how to calculate them. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Simultaneous Linear Equations Part 1
The purpose of this section is to look at the solution of simultaneous linear equations. We will see that solving a pair of simultaneous equations is equivalent to finding the location of the point of intersection of two straight lines. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Completing the Square - by Inspection
In this unit we consider how quadratic expressions can be written in an equivalent form using the technique known as completing the square. This technique has applications in a number of areas, but we will see an example of its use in solving a quadratic equation. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Integration using trig identities or a trig substitution
This unit explains how trig identities and trig substitutions can help when finding integrals. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Exponential and logarithm functions
Exponential functions and logarithm functions are important in both theory and practice. In this unit we look at the graphs of exponential and logarithm functions, and see how they are related. (Mathtutor Video Tutorial) This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Quadratic Equations 10
This unit is about the solution of quadratic equations. These take the form ax2+bx+c = 0. We will look at four methods: solution by factorisation, solution by completing the square, solution using a formula, and solution using graphs. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Quadratic Equations 2
This unit is about the solution of quadratic equations. These take the form ax2+bx+c = 0. We will look at four methods: solution by factorisation, solution by completing the square, solution using a formula, and solution using graphs. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Quadratic Equations 3
This unit is about the solution of quadratic equations. These take the form ax2+bx+c = 0. We will look at four methods: solution by factorisation, solution by completing the square, solution using a formula, and solution using graphs. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.
Resource type Quadratic Equations 5
This unit is about the solution of quadratic equations. These take the form ax2+bx+c = 0. We will look at four methods: solution by factorisation, solution by completing the square, solution using a formula, and solution using graphs. This resource is released under a Creative Commons license Attribution-Non-Commercial-No Derivative Works and the copyright is held by Skillbank Solutions Ltd.

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